Question

Please answer right thanks :) want to learn!

Its a two parter I think since he lumped them together.

1)

A point charge is located at the center of two thin, concentric, non-conducting spherical shells (both charged). The flux through a gaussian sphere of varying radii (centered at point P) is as follows:

$LaTeX: \Phi_e$Φ e =1.88 x 10⁶ Nm²/C (for r < r₁);

= -2.1 x 10⁶ Nm²/C (for r₁ < r < r₂);

= 3.3 x 10⁶ Nm²/C (for r > r₂).

What is the charge at point P? Give your answer in µC but enter only the numerical part.

2)

A point charge is located at the center of two thin, concentric, non-conducting spherical shells (both charged). The flux through a gaussian sphere of varying radii (centered at point P) is as follows:

$LaTeX: \Phi_e$Φ e =1.4 x 10⁶ Nm²/C (for r < r₁);

= -1.5 x 10⁶ Nm²/C (for r₁ < r < r₂);

= 4.3 x 10⁶ Nm²/C (for r > r₂).

What is the charge on shell 2? Give your answer in µC but enter only the numerical part.

Answer 1

PPLEASE GIVE A LIKE.

E. a Gaussian just calculate 1) We know Dez fE.ds - Genealosed - To determine charge P. we consider Surface around it. But we have to charge so So , 0 = enclosed 9 = Octo pe = 1.88 x 109 Nm/_fer = 8.85 x 10-12 So 9 = (1,88 x106) 8.85 x 1012) _693 16.638 uc Go , I (2) on to calculate charge In this part we have shell 2 - So at point P $ = IP Co 9. Charge at P Q = (1.4 x 106 x 8.8 5x10-12) = 12.39 uc

flux of Shell 1 5 = p + , (-1.5 x 166 x 8 - 9 s v10-12-) = 12. 34 , 4а, - 13, 28 мс = 12 390 - , - -25. Са и . flux of shell 2 фа (р. 1 Ч. + 4 - (437 (66) (3.8 5 x 16-1") = (12. 31 - 2 5.67) + 0 30. 06 Дc = -13. 2 0 +4.. 1 2 = 51. 3ч Ас