Homework Answers
a) Probability = P(First defective) * P(Second defective | First defective) = (60/5000) * (59/4999) = 0.00014163
b) Probability under independence assumption = (60/5000) * (60/5000) = 0.00014400
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Save Homework: Section 5.4 Homework Score: 0 of 10 pts 13 of 13 (9 complete) HW...
Suppose that a computer chip company has just shipped 10 comma 000 computer chips to a...
Suppose that a computer chip company has just shipped 10 comma 000 computer chips to a computer company. Unfortunately, 60 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) The probability that the first randomly selected chip is defective is StartFraction 60 Over 10 comma 000 EndFraction equals 0.006 equals 0.6 % . Compute the probability that two randomly selected chips are defective under the assumption of independent events.
Suppose that a computer chip company has just shipped 10,000 computer chips to a computer company.
Suppose that a computer chip company has just shipped 10,000 computer chips to a computer company. Unfortunately, 60 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) The probability that the first randomly selected chip is defective is 60/10,000 = 0.006 = 0.6%. Compute the probability that two randomly selected chips are defective under the assumption of independent events. (a) The probability is _______ (Round to eight decimal places as needed.)
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