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Homework: HW 4 Save Score: 0 of 1 pt 12 of 30 (11 complete) HW Score: 33.33%, 10 of 30 pts cess 5.2.15-T Question Help Assume

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Answer #1

Here, μ = 269, σ = 11, x1 = 284 and x2 = 294. We need to compute P(284<= X <= 294). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ
z1 = (284 - 269)/11 = 1.36
z2 = (294 - 269)/11 = 2.27

Therefore, we get
P(284 <= X <= 294) = P((294 - 269)/11) <= z <= (294 - 269)/11)
= P(1.36 <= z <= 2.27) = P(z <= 2.27) - P(z <= 1.36)
= 0.9884 - 0.9131
= 0.0753

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