According to the reaction below, how many grams of zinc, Zn, could react in 151.46 mL...

Question

Question

According to the reaction below, how many grams of zinc, Zn, could react in 151.46 mL of 1.084 M AgNO₃?

Zn(s) + 2 AgNO₃(aq) → 2 Ag(s) + Zn(NO₃)₂(aq)

Answer 1

Answer #1

② The geven reaction is - - Zn(s) + 2 AgNO3(aq) + 2 Ag(s) + Zn (NO3)2 Now, molecular weight of AgNO3 = 108+14+(1643) =170 gmi

Answer 2

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