Question

Question 5 20 marks Given: The hand-crank shown below has a thrust bearing at A and journal bearing at C as shown below. There is a load applied at B and at D as shown in the sketch. The crank is in equilibrium and the weight of the crank is negligible. Required: Determine the reactions on the crank from each of the bearings (A & C. Note: A journal bearing only has reaction forces perpendicular to the shaft (x and y directions at C) where as the thrust bearing has reaction forces perpendicular to the shaft and in the direction of the axis of shaft (x, y, & z directions at A) 200 200 mm 100 N 300 mm 300 mm 1100 mm 160 mm F,= (-50 N 1) + (-10 N k) 80mm Solution Rax (N)= RAY (N)= RAZ (N)= -15 47.3 -10 Rex (N)= Rcy (N)= 65.0 52.7

Answer 1

Write coordinates Lo,o, 01 lo, o0.6J C L-o 2 0,0.3] m DIO0-16, o.18 Forces Wnite for m in vector FD Ni Jo N K Eq.CI) B -l00 £9.(2) Ay j Ax i Az k + Eq.(3) Cr i £q.C9) MeA Take Moment due to FD Y AD o16 -50i-10 to78 k + 16 39 Eq Cs)

Moment Adue to YAB 100 +0.3k 20 k +30 & EqC6) Moment Eq C7) due to A Moment A due to YAC X C +Cyil O.6 lk 0.6 Cx Take Mx eA -O Components Eq (s) to (8) of J.6 +30 .. O o6 Cy 31-6 key 52.7

of i components M4 eA 0 / Ea C5)to (8) -o 39 + 0.6 Cx Cx = 39 65 N Cx-Rex FoYce equilibzium Now, Take ie ti oF Eas. D to (4)-o Ax t C O -50 + Ax t65 =O -65 50o Ax Ax- GF E5.(1) to c4)-0 je -100 + Ay +Cy 100 Ay +52.+ P.y 44.3 N k OF Eas. C1) to C4) -O FL O iey -lo + AZ AZ- 10