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Problem 1 (40 points) The rotational system shown in this diagram has a single torque input, T(t), and a single angular displPARTS: a-c

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Answer #1

The governing differential equation is given to be

-J0+20+ k =T

(1) - - في =ة.-

Defining the following state variable (1) = 0;r(2) = 0 =r(1)

Using the state variable, we can reduce the second order differential equation (1) to two first order differential equations which can be represented in a matrix form as follows

d/1 dt (x(2) 0 1-4 11/21) + OT - x(2)

Therefore,

\small A=\begin{bmatrix} 0 &1 \\ -\frac{k}{J} &-\frac{c}{J} \end{bmatrix}; B=\begin{Bmatrix} 0\\\frac{1}{J} \end{Bmatrix}

The output vector can be written as

2 = 0 il r(2)
Therefore,

\small C=\begin{bmatrix} 1 &0 \\ 0& 1 \end{bmatrix}; D= \begin{Bmatrix} 0\\0 \end{Bmatrix}

The eigenvalues of matrix A can be found by solving the following equation

det|A-X1=0det 1-1 - - 1 +1)]

-:12+ft+ = 0

Therefore, the eigenvalues are

-..--+ V(5)? - -4-(5):- 4

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