Question

i Ch. 9 Homework C) 10 of 1 What is the mamum number of moles of Py0, hat can thecreically be made from 240g of Oy and encess Express your answer to three significant figures and include the appropriate units Learning Goal: View Available Hints) 3.00 mol Eevious Answers with ive moles of oxygen, Oa. to produce two moles of diphosphonus pentoxide, P10 umber where you are given the mole enough axygen number of moles of produc(3.00 mol Py0s) formed from the given amount of oxygen and excess phesphous Now, debermne the number of moles of P0, s produced ftrom the given amounts of phonphorus and oxygen Express your answer to three significant figures and include the appropriate anits product. The product that can be made, also known as the heorical yeld neactants, you wit rst hawe to If you are given the masses of the convert to moles Once you have mole above, applying the ratos shown in the balanced Units Prarson

Answer 1

the reaction is

P₄ + 5 O₂ → 2 P₂O₅

given

240 g of O2

no of moles of O₂ = mass / molar mass of O₂ = 240 / 32 = 7.5

From the reaction we can say 5 moles of O₂ gives 2 Moles of P₂O₅

For 7.5 moles of O₂ no of moles of P₂O₅ produced is 7.5 * 2 / 5 = 3 moles of P₂O₅

Part C

From the question 3.40 Mole P₂O₅ formed from phosphorous and excess oxygen , 3 Mole P₂O₅ formed from Oxygen and

excess phosphorous

From this result we can conclude that less no of moles of P₂O₅ is obtained from oxygen hence oxygen is the limiting

reagent

so the theoretical yield will be the no of moles of P₂O₅ obtained from the limiting reagent

Hence

number of moles of P₂O₅ produced from the given amounts of phosphorus and oxygen is 3 moles