Question

Find I, in the network in the figure. 5 11m 2 kn mA

Answer 1

The given circuit is:

Solution :

5krz 11 MAI 2K2} {aks I.

From the circuit , it is clear that all the elements are in parallel.

Since we've to find the current $\large I_o$ in the 2 k Ohm resistor, so let this 2 ohm resistor as it is. And find the equivalent of the other two parallel resistors of.

2Ω & 5kΩ

11MA D 32 ka 2K2 & 5kr & Io

So, the equivalent of    will be:

2Ω & 5kΩ

X Req=5 NN = 1.43 k2 +

Final circuit diagram:

Rea = 1.43 kr 11 mA (1)

Now we can easily use current division rule.

According to Current division Rule:

Y I ER Y I ER I

The current in $\large R_1$ will be given by:

R2 11=1 Ri + R2

similarly

R1 12 = 1 Ri + R2

so , Using this rule we can find

$\large I_o$ :

Since the direction of $\large I_o$ is opposite to that we may find by current division rule,

so,

1.43 1. = -11 x 2 +1.43 => 1,= -4.59 mA .......... Answer