6)
null hypothesis:Ho:distribution Grades distribution in sample is same as distribution in population. |
Alternate hypothesis:Ha:distribution Grades distribution in sample is not same as distribution in population. |
degree of freedom =categories-1= | 4 | |||
for 0.05 level and 4 df :crtiical value X2 = | 9.488 | |||
Decision rule: reject Ho if value of test statistic X2>9.488 | ||||
applying chi square goodness of fit test: |
relative | observed | Expected | residual | Chi square | |
category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)/√Ei | R2i=(Oi-Ei)2/Ei |
A | 0.100 | 6.000 | 5.400 | 0.26 | 0.067 |
B | 0.230 | 14.000 | 12.420 | 0.45 | 0.201 |
C | 0.450 | 22.000 | 24.300 | -0.47 | 0.218 |
D | 0.140 | 8.000 | 7.560 | 0.16 | 0.026 |
F | 0.080 | 4.000 | 4.320 | -0.15 | 0.024 |
total | 1.000 | 54 | 54 | 0.5347 | |
test statistic X2 = | 0.535 |
since test statistic does not falls in rejection region we fail to reject null hypothesis |
we do not have have sufficient evidence to conclude that distribution of grades differ from claimed by teacher |
please with chi chart thank you An anatomy teacher hypothesizes that the final grades in her...
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