10.
Type |
Number Sold (O) |
Expected (E) |
D = (O -E) |
D^2/E |
Spearmint |
25 |
29.5 |
-4.5 |
0.686441 |
Wintergreen |
32 |
29.5 |
2.5 |
0.211864 |
cherry |
18 |
29.5 |
-11.5 |
4.483051 |
Cinnamon |
43 |
29.5 |
13.5 |
6.177966 |
118 |
11.55932 |
The chi square value is given by
From the above table, chi square test value = 11.56
11.
A contengency table has 5 rows and 4 columns. The degrees of freedom is given by
Degrees of freedom = (5 – 1)*(4 – 1) = 4*3 = 12
12.
The degrees of freedom = (5-1)*(5-1) = 4*4 = 16
The critical value at α = 0.05 and df = 16 is 26.296.
13.
The degrees of freedom is (5-1) = 4
The critical value at α = 0.05 and df = 4 is 9.488.
A chewing gum manufacturer wishes to determine if his customers prefer one flavor gum to any...
1. Two manufacturing processes are being compared to try to reduce the number of defective products made. During 8 shifts for each process, the following results were observed: Line A Line B n 181 | 187 Based on a 5% significance level, did line B have a larger average than line A? *Use the tables I gave you in the handouts for the critical values *Use the appropriate test statistic value, NOT the p-value method *Use and show the 5...