Asteroid Bearcat has a orbital period of 2000 years. What is its semi-major axis in AU?

Question

Question

Answer 1

Answer #1

This can be determined by using the Kepler's 3rd law which suggests that T²=a³

Where T= time period/orbital period and a= semi-major axis

2000= a³, (44.72)²= a³, (44.72)²= (44.72)³, 2000= 89434.562

So for 2000 years orbital period, 89434.562 AU is the semi-major axis.

Answer 2

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