Problem 5 An air-filled toroidal solenoid has a mean radius of 15.4 cm and a cross-sectional...

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Answer 1

Answer #1

E = 1/2 L I²

L = 2 E / I² = (2 * 0.395) / (12.5²) = 5.056 * 10^-3 H

L = mu₀ N² A / 2 pi R

N = sqrt [2 pi R L / mu₀ A]

= sqrt [2 pi * 0.154 * 5.056 * 10^-3 / 4 pi * 10^-7 * 4.95 * 10^-4]

N = 2804 turns

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Answer 2

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