Question

An article reported the following data on oxygen consumption (ml/kg/min) for a sample of ten firefighters performing a fire-suppression simulation: 29.5 49.6 30.4 28.6 28.8 25.1 33.3 29.8 23.7 30.0 Compute the following. (Round your answers to four decimal places.) (a) The sample range ml/kg/min (b) The sample variances from the definition (t.e, by first computing deviations, then squaring them, etc.) ml?/kg/min? (c) The sample standard deviation ml/kg/min (d) s using the shortcut method ml?/kg/min? Need Help? Read It Tak to Tutor

Answer 1

Date set I 29.5, 49.6,30-4, 98.6,988, 95.1, 33-3,298,93.7,30-0 na 10 la) Lowest value = 23.7 Highest value = 49.6 Range = Highest value- lowest value = 49.6 -23.7 - (259) mo. 16). mean (8) - Ex - 308*8 = 30.88 Sample varianegº) = (x - 52 h-1 = (29-5-30188) +--+(39.0 - 30-93)? 10-1 454.856 50.539556 5° = 50.594m

(c) Sample Standard deviation (s) = E(**»)" hol ((99.5-30-82)-- + (30-0-30-23) 101 454.856 50.539556 = 7.1091 Ans X = 29.5 +49.6.+ 30.4 +986 + 98-8 +251 +33.3+29.8+ 23.7+300 - 308.8 2 XP 29.5+ 49.6+ 30.42 +28-6°+98.8°79509++ 33-3*+ 39.84 +237 +30.0° = 19906 for short but method, s² = hh (Ex- (Ex)") - (99506 - 95357044) = 50.539556 2 50.5396 s+ = 150.5396) Ang