21)
Answer)
As there are fixed number of trials and probability of each and every trial is same and independent of each other
Here we need to use the binomial formula
P(r) = ncr*(p^r)*(1-p)^n-r
Ncr = n!/(r!*(n-r)!)
N! = N*n-1*n-2*n-3*n-4*n-5........till 1
For example 5! = 5*4*3*2*1
Special case is 0! = 1
P = probability of single trial = 0.05
N = number of trials = 5
R = desired success = exactly 2
P(2) = 5c2*(0.05^2)*(1-0.95)^5-2 = 0.021434375
You can look into binomial table
For n = 5 and x = 2
B)
P(x>2)
= P(3) + p(4) + p(5)
= 0.001158125
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