Question

- 17 days 4/13 Content attribution FEEDBACK QUESTION 5 . 1 POINT If 1.09 g of glucose are burned in a bomb calorimeter, the temperature of the 900. g of water in the calorimeter increases from 15.50 °C to 19.30 °C. If the heat capacity of the calorimeter is 680..what is the value of g for the combustion of the glucose sample? Use water = 4.184 Provide your answer below: FEEDBACK Content attribution QUESTION 6.1 POINT A process that absorbs heat is called a(n) process.

Answer 1

Question 5;

Heat change of water + Heat change of calorimeter (q_s)

= (Mass of water × specific heat of water + heat capacity of calorimeter) × $\Delta$ T

Or, q_s

= [900 (g) × 4.184(J/g^oc) + 680 (J/^oc)] × (19.30 - 15.50)^oc

Or, q_s= (4445.6 × 3.8) J

Or, q_s= 16893 J

q_s= (16893/1000) KJ.

Or, q_s= 16.89 KJ.

Heat change of combustion of glucose(q) = - q_s

Now, q for combustion of the glucose sample

= - q_s

= - 16.89 KJ.

= -16.9 KJ ( 3 significant figure)

Question 6:

The process that absorbed is an endothermic.

Endo means internal and thermo means heat.

In endothermic process heat is added to a system