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Give all areas as percent (to the nearest tenth). 3. For each of the following: Shade the graph, then answer each of the foll
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Answer #1

We find these probability using standard normal distribution table

B) area to left of x is 12.3%

Then area to the right of x is 100%-12.3%=87.7%

C) area to the right of x is 54.3%

Then area to the left of x is 100%-54.3%=45.7%

For D andE we use standard normal distribution table solutions to file is attached go through it

Shaded region is askef area to find

Plant At z=-1-16 P(27-1-16) - 87.74 Area to left of n = 0.123 = 12:30/1 Area do Right of his 100 yor 12.3% = 87.7% 22006 200

Thanks

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