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![Applying Law of Chemical equilibrium, the expressure for Kp is (Pnzo) 7120 2 kp=4.0658]](http://img.homeworklib.com/questions/22c02430-a013-11ea-a74b-cd25e94d8329.png?x-oss-process=image/resize,w_560)
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2. In a study of the reaction 3Fe (1) + 4H20) Fe3O4 (0) + 4H2O at...
In a study of the reaction below at 1199 K, it was observed that when the...
In a study of the reaction below at 1199 K, it was observed that when the equilibrium partial pressure of water vapor is 53.4 torr, the total pressure at equilibrium is 68.2 torr. Calculate Kp for this reaction at 1199 K. 3 Fe(s) + 4 H2O(g) equilibrium reaction arrow Fe3O4(s) + 4 H2(g)
In a study of the reaction below at 1199 K, it was observed that when the...
In a study of the reaction below at 1199 K, it was observed that when the equilibrium partial pressure of water vapor is 55.4 torr, the total pressure at equilibrium is 70.7 torr. Calculate Kp for this reaction at 1199 K. 3 Fe(s) + 4 H2O(g) <==> Fe3O4(s) + 4 H2(g) Can I get this written out? How do you know which part of the equation goes on top for finding Kp?
Consider the reaction: Fe3O4(s) + 4H2(g)—>3Fe(s) + 4H2O(g) Using standard absolute entropies at 298K, calculate the...
Consider the reaction: Fe3O4(s) + 4H2(g)—>3Fe(s) + 4H2O(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.79 moles of Fe3O4(s) react at standard conditions. ASºsystem = J/K
1.) Consider the reaction: Fe3O4(s) + 4H2(g)3Fe(s) + 4H2O(g) Using standard thermodynamic data at 298K, calculate...
1.) Consider the reaction: Fe3O4(s) + 4H2(g)3Fe(s) + 4H2O(g) Using standard thermodynamic data at 298K, calculate the free energy change when 2.48 moles of Fe3O4(s) react at standard conditions. G°rxn = kJ 2.)Consider the reaction: H2(g) + Cl2(g)2HCl(g) Using standard thermodynamic data at 298K, calculate the free energy change when 1.750 moles of H2(g) react at standard conditions. G°rxn = kJ
3. For the dissociation of gaseous PCls, the value of K, 2.00. The equilibrium reaction is...
3. For the dissociation of gaseous PCls, the value of K, 2.00. The equilibrium reaction is PCMs) + Cl2(g) pressure of a sample of PCl, is kept constant at 5.00 atm during PCI(g) If the initial total the reaction, what would be the partial pressures of reactant and products when equilibrium is reached? - Write the K,equilibrium constant expression - Write expression of Dalton's law for the partial pressure for this reaction - Tabulate the changes of partial pressures -...
Consider the reaction: CO(g) + H2O(g) -><- CO2(g) + H2(g) Kp = 0.0871 at 1000 K...
Consider the reaction: CO(g) + H2O(g) -><- CO2(g) +
H2(g)
Kp = 0.0871 at 1000 K
A reaction mixture originally contains a CO partial pressure
of 1744 torr and a H2O partial pressure of 766 torr at 1000 K.
Caluculate the equilibrium partial pressures of each of the
products
6) (10 points) Consider the reaction: CO(g) + H2O(g) = CO2(g) + H2(g) Kp = 0.0871 at 1000 K A reaction mixture initially contains a CO partial pressure of 1 744...
1. If the atmospheric pressure was 765 torr and the partial pressure of air was 745...
1. If the atmospheric pressure was 765 torr and the partial pressure of air was 745 torr, calculate the partial pressure of water vapor using Dalton's Law. Perial - P. + P2! 765 forr = 745 torr & P2 P = 20 tour -795 torre 2. Refer to the "y = mx + b" (linear) form of the Clausius-Clapeyron equation on the first page of this experiment. What part of the Clausius-Clapeyron equation is equal to the slope: slope =...
Unknown sample no. C Trial I Trial 2 1. Mass of 2. Mass of generator + sample before reaction () ...
help
with remaining calculations please
Unknown sample no. C Trial I Trial 2 1. Mass of 2. Mass of generator + sample before reaction () 3. Inst s approval of apparatus C. Determination of Vol ume, Temperature, and Pressure of the Carbon Dioxide Gas 1. Initial reading of volume of water in CO.-collecting graduated cylinder (mL) 2. Final reading of volume of water in CO-collecting graduated cylinder (mL) 3. Volume of CO,(g) collected (L) 4. Temperature of water C) 5....
Please answer the whole page. Ideal Gas Law PV = nRT Gas Laws Formulas Combined Gas Law (P1)(V1) Ti (P2)(V2) Tz = Dalto...
Please answer the whole page.
Ideal Gas Law PV = nRT Gas Laws Formulas Combined Gas Law (P1)(V1) Ti (P2)(V2) Tz = Dalton's Law of Partial Pressures P = P, +P+P, + ...etc. K="C + 273 3. A 5.0 L sample of gas has a pressure of 1200 torr. What is the new pressure if the temperature is changed from 220 K to 440 K and the volume increased to 20.0 L ? 4. A 10.0 mL sample of gas...
show calculations. 5-1, please. Unit 5: Gases Ato Basic Gas Relations . onsider the Ideal Gas...
show calculations. 5-1, please.
Unit 5: Gases Ato Basic Gas Relations . onsider the Ideal Gas Law: where n is the number of moles, P is the pressure in atm nRT wnere n is the number of moles, P is the pressure in atm, is the vol ume in L, T is the absolute (Kelvin) temperature, and R = 0.082 L atm/mole K ote: 1. Parameters that are on oppos1te sign are directly proportional to ea 2. Parameters that are...
Consider the reaction: Fe3O4(s) + 4H2(g)—>3Fe(s) + 4H2O(g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.79 moles of Fe3O4(s) react at standard conditions. ASºsystem = J/K
3. For the dissociation of gaseous PCls, the value of K, 2.00. The equilibrium reaction is PCMs) + Cl2(g) pressure of a sample of PCl, is kept constant at 5.00 atm during PCI(g) If the initial total the reaction, what would be the partial pressures of reactant and products when equilibrium is reached? - Write the K,equilibrium constant expression - Write expression of Dalton's law for the partial pressure for this reaction - Tabulate the changes of partial pressures -...
Consider the reaction: CO(g) + H2O(g) -><- CO2(g) +
H2(g)
Kp = 0.0871 at 1000 K
A reaction mixture originally contains a CO partial pressure
of 1744 torr and a H2O partial pressure of 766 torr at 1000 K.
Caluculate the equilibrium partial pressures of each of the
products
6) (10 points) Consider the reaction: CO(g) + H2O(g) = CO2(g) + H2(g) Kp = 0.0871 at 1000 K A reaction mixture initially contains a CO partial pressure of 1 744...
1. If the atmospheric pressure was 765 torr and the partial pressure of air was 745 torr, calculate the partial pressure of water vapor using Dalton's Law. Perial - P. + P2! 765 forr = 745 torr & P2 P = 20 tour -795 torre 2. Refer to the "y = mx + b" (linear) form of the Clausius-Clapeyron equation on the first page of this experiment. What part of the Clausius-Clapeyron equation is equal to the slope: slope =...
help
with remaining calculations please
Unknown sample no. C Trial I Trial 2 1. Mass of 2. Mass of generator + sample before reaction () 3. Inst s approval of apparatus C. Determination of Vol ume, Temperature, and Pressure of the Carbon Dioxide Gas 1. Initial reading of volume of water in CO.-collecting graduated cylinder (mL) 2. Final reading of volume of water in CO-collecting graduated cylinder (mL) 3. Volume of CO,(g) collected (L) 4. Temperature of water C) 5....
Please answer the whole page.
Ideal Gas Law PV = nRT Gas Laws Formulas Combined Gas Law (P1)(V1) Ti (P2)(V2) Tz = Dalton's Law of Partial Pressures P = P, +P+P, + ...etc. K="C + 273 3. A 5.0 L sample of gas has a pressure of 1200 torr. What is the new pressure if the temperature is changed from 220 K to 440 K and the volume increased to 20.0 L ? 4. A 10.0 mL sample of gas...
show calculations. 5-1, please.
Unit 5: Gases Ato Basic Gas Relations . onsider the Ideal Gas Law: where n is the number of moles, P is the pressure in atm nRT wnere n is the number of moles, P is the pressure in atm, is the vol ume in L, T is the absolute (Kelvin) temperature, and R = 0.082 L atm/mole K ote: 1. Parameters that are on oppos1te sign are directly proportional to ea 2. Parameters that are...
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