F = 47.1N
r = 1.76m
Since force is perpendicular to the door
Torque = Force × length = 47.1×1.76 = 82.896 N.m
=) T = 82.896N.m
Required information X m 43.0° Axis where x = 1.76. As shown in the top-view diagram,...
part c=d
How much force must you and your friend each apply to the free
end of the door on the same side and perpendicular to the plane of
the door in order to produce the same torque as that produced by
both of you in part (a) above?
N
(d) What is the angular acceleration of the door?
rad/s2
A heavy swing door has a mass of m = 7,500 kg, a width W = 1.9 m, and a...
can
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. mn A heavy swing door has a mass of m 3,000 kg, a width W 1.7 m, and a height door about the vertical axis of rotation is given by T m w . F-9.0 N. Your friend pushes on the other outer edge of the (a) You stand on one side and puth at the outer edge of the door and...
Sakai @ PC: Gateway: Welcome Google Slides Rotational Motion and Oscillations - EPS 101, section o -/4 POINTS OSUNIPHYS1 10.7.WA.057. MY NOTES ASK YOUR TEACHER A heavy swing door has a mass of m - 4,000 kg, a width w = 1.4 m, and a height H - 2.9 m. The door swings about a vertical axis passing through its center. The moment of inertia of this door about the vertical axis of rotation is given by I m w....
Q5
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wrong one.
A heavy swing door has a mass of m = 4,000 kg, a width w = 1.0 m, and a height H = 2.7 m. The door swings about a vertical axis passing through its center. The moment of inertia of this door about the vertical axis of rotation is given by I = 1/12 mw^2. (a) You stand on one side and push...
A door shown in the figure) undergoes rotational motions about the vertical axis. The governing equation of rotational motion is given by Jyö + C70 + k 0 = 0 where Jo is the moment of inertia of the door, Ct is the rotational viscous damping and kt is the rotational stiffness of the door hinge. Assume that the door is 0.8 m wide (L = 0.8 m) and has a mass m of 15 kg. The moment of inertia...
#4
For problem 3-5, consider a top-down view of a door, as shown below: -D 3.Where on the door (and in which direction) would you apply a force to exert the greatest torque? (The forces are shown in the sketch.) D) D A) A B)B ー.which of the forces result in the least amount of torque? ADA B) B C)cD E) Both A and D A s The torque from force C (end) is ded the torque from force B...
3. Three forces are acting on a rigid body as shown in the top view diagram below. F =200 N E=300 N 90 cm 10cm F,=100N (a) Is this body in equilibrium? (b) If not, what is the magnitude and direction of a fourth force which could be applied to the body in order to place the body in equilibrium? (c) Where, along the body, must this fourth force be applied? 11/3/2017 -7-
top view side view The picture shows a rectangular current-carrying loop in a uniform magnetic field that is directed right. The loop is free to rotate about the axis shown as the dashed line in the top view. (a) Select all the correct statements about this situation from the list below As seen from the side view, the initial net torque on the loop is clockwise As seen from the side view, the initial net torque on the loop is...
What factors determine the torque generated by a force? Select ALL factors. distance between where force is applied and the axis of rotation whether the force is conservative or non-conservative. magnitude of the force orientation of the force. A force F is applied at the position shown where is the vector from the axis of rotation to where the force is applied. The notation on the diagram is: r=|| F ||and F =|| F | F and F. - components...
A hinged water storage is shown below. Its top side is denoted as C, the narrow side as B and the long side as A. Assume water density is 1000 kg/m3 and gravity is 9.81 m/s2 Side A is hinged at the bottom edge and secured using a clasp at its top edge centre position. Dimensions are: L = 0.8m, H = 0.6m & W = 0.4m When the tank is full of water: a) Calculate the size and location...