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2. With the imminent new cigarette packaging legislation, there is a lot of interest at the moment in the proportion of Austr
3. Question 2 continues. Test whether there is evidence at the 5% level of significance that the percentage of Australians ag
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Answer #1

2)
p^ +- z * sqrt(p^ * (1-p^/n))

X = 784, n = 5000

p^ = X/n = 0.1568, z = 1.96 for 95% CI

Population PROPORTION Confidence Interval
sample size = 5000
sample proportion = 0.1568
confidence level = 95%
Number of Decimals in Results = 4
standard error = 0.005142
Critical z-value = 1.959964
Confidence Interval = 0.1568 +/- 0.0100786280273571
= ( 0.146721371972643, 0.166878628027357)
( 0.1467, 0.1669)
We are 95% confident the true population proportion is between 0.1467 and 0.1669.

3)

Population PROPORTION Hypothesis Test
phat = sample proportion = 0.1568
n = sample size = 5000
α = alpha = 0.1
Step 1: State Ho and Ha
Population parameter comparison value? 0.15
Is this a LEFT, RIGHT or TWO tailed test? RIGHT-tailed
Null Hypothesis: Ho: p ≤ 0.15
Alternate Hypothesis: Ha: p > 0.15
Step 2: State Decision Criteria; Find Critical Values
Reject Ho if z > 1.282
or Reject Ho if p-value < α = 0.1
Step 3: Calculate Test Statistic
Test statistic = z = 1.346600658
p-value = 0.089054441
Step 4: Make Decision
Reject Ho
Reject Ho since p-value (0.0891) IS less than α, alpha, = 0.1.
Also, Reject Ho since the Test statistic (1.3466) meets the rejection criteria in STEP 2.
Step 5: Summarize Decision
There is sufficient statistical evidence to reject Ho.

Please give me a thumbs-up if this helps you out. Thank you! :)

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