Question

When two volatile liquids, X and Y, are mixed, the solution process involves 1. breaking the intermolecular X--X and Y...Y attractions, and 2. forming new X...Y attractions. Complete the table describing how the relative strengths of these attractive forces affect vapor pressure and enthalpy of solution. Raoult's law deviations AH Strength of the attractive forces X X , Y..Y, and X...Y are equal X...Y is strongest X...Y is weakest Answer Bank negative positive zero

Answer 1

solutions :- Strength af attractive forces Raoults low deviation DMsoulos (3ero x-x,y...y and x-..y are equall sero) x...y is strongest negative (Positive X...y is weakest (negating Positis Explanaters :- ayx y, y..y and X...y attracters are sanm then solution will be ideal c-e- no deviations from ideal behavior. y x-ry attracts in greater than x-x and Y...y attraction then boiling point al solution will be higher and hence low vapor pressure Y X--.y attractions is weakes than X--X and Y...y attraction then boiling point al solutions will be lewer then expected and heno highs Vapor Fressine then the expected vaper pressure