Question

Record the input and output voltages from the following frequencies for the low-pass fiter (Fig. 11.2). 100 200 500 1000 2000
For the low pass filter plot the ratio, Vout/Vin as a function of frequency on the same graph. La- bel the plot as RL. Draw
vin =V1+ /R2 (lowpass) 4D5 (low pass), out 1+X/R2 (high pass), and
0 0
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Answer #1

Data Display Default: A YO B X = 3177.86923, Yー-00965156794 || Polynomial Fit of Sheet1 D 0.8 0.4 0.2 0.0 2000 2000 4000 6000

This is the graph plotted using the data points, with frequency in X axis and Vout/Vin in Y axis.

The frequency at which Vout/Vin = 1/sqrt 2 = 3177.869 Hz

we know,

0.707 = 1/(1+(XL2/27002))0.5

XL= 2700.8155 ohm

From, XL = 2 * 3.14 * f * L

we have L = XL /2*3.14*f

L = 0.1353 H

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