Question

A 50 kW load operates from a 60 Hz and 10kV line with a power factor of 0.6 lagging. Compute the capacitance that must be placed in parallel with the load to achieve 0.9 lagging power factor.

In-Class #10 Problem A 50 kW load operates from a 60 Hz and 10 kV line with a power factor of 0.6 lagging. Compute the capacitance that must be placed in parallel with the load to achieve 0.9 lagging power factor.

Answer 1

Page 1

P. Load power p = 50kW frealency f = 50HZ Line voltage Vc = IOKV Initial power factor (ose) = 0.6 lag New power factor Cost2 – 0.9 lag Ø 1= Coil (oob) = 53.13° 02 = Conco.a) = 25.84 Capacitoo to The reactive power supplied foom improve power factor from 0.6 log tooqlag is

Page 2

Qc = P(tandi – tan62) = 50kw Cų - 0.4843) = 42.45 Kvar. It is known that Qc = X Qc = ULLY WC uc Qc = VLL WC с= Qс View 42.45 x 10 10²x106 x 2XITX 60 C – 1.126 Mfarad. Capacitance must be placed in parallel with load is C = 1.126 MF.