Question

Consider the following observations on a receptor binding measure (adjusted distribution volume) for a sample of 13 healthy individuals: 22, 39, 40, 41, 43, 48, 52, 59, 62, 67, 68, 69, 72. (a) Is it plausible that the population distribution from which this sample was selected is normal? ---Select--- , it ---Select--- plausible that the population distribution is normal. (b) Calculate an interval for which you can be 95% confident that at least 95% of all healthy individuals in the population have adjusted distribution volumes lying between the limits of the interval. (Round your answers to three decimal places.) (c) Predict the adjusted distribution volume of a single healthy individual by calculating a 95% prediction interval. (Round your answers to three decimal places.) How does this interval's with compare to the width of the interval calculated in part (b)? This interval's width is ---Select-- than the width of the interval calculated in part (b).

Answer 1

1 NI solition Given data * n=13 $ 22, 39,40,41,43.48,52,59,62,64,68,69,72. cod we have to find 95% confidence interval 95% cf for te= 0.05 df (12) te Q. 179 Meau @): $x 10-22+35+"it72 -(52467 sp -* *** (15:13] 95%. cf. tits Elmo) = 52461 2.149 445:13) = 52:46+ 2.179x4.196 - 52.461 9.144 956 CP = 43.3162 161.604) cas ches] it is plausible that the population distribution is normal. (c) we find gol. Prediction Interval 95.). PI = I texs ulti) 52.467 2:149 x 15-13x1-038 -52-UG 34.213 954. PI = (18.247 86.673] 954 c width = 61.604 - 43.316 3 (18.238 951. PI had th = 86.673 -13.247 = 168.42.61 This intervals width is greater than the width of interval part (6)