Question

2. Thave 2 equally strong positive charges that I've bolted to the ground. Where can I put a 3rd (mobile) test charge, such that it doesn't feel an overall force from them? What changes if one of those original charges is negative? 3. I have 2 conducting plates, both weighing mass M, with charges q1 and 92 (that I control) on each respectively. I bolt one plate to the ground so it can't move, and I want to levitate the other plate 1 meter above it: what do I need to do to accomplish that? What would change if I wanted to levitate it 3 meters above?

Answer 1

q=%=9 q,4 quis bositive Charge qis kositive test charge Force on a due to q, is f kq, q kq q 22 fo, & fog are in opposite direction. Distance & from of a forom a, where het change on q, is zero - Force E, E 270 ) F, = Fja (2-x) a x2 2-1= x x= 2/2 So at mid boint b/w 9,4 % where net force is zeroong. 7 Let asume q, is negative 9,=-q O+x - o d o the x-ar's Fj, a kaq F = k qq (2+x2 free to 7 F,-F 70 VK&q) =* ua x2 (2+xyz (2+2)2 = x² 2² +22+ 224 = 222 27 = -28X [x = -2 Now netforce zor on Vy is X=- a means Left side of q, at a distance x=-2/2 e