Question

Practice Problem 12.122 You have two solutions, one 1.50 M sodium sulfide and the other 1.00 M Pb(NO3)2-

Answer 1

Following is the - complete Answer -&- Explanation: for the first question ( i.e. Question related with sodium sulfide,

Na₂S , and Pb(NO₃)₂ ) , ...in....image format....

ER SOLUTIONS Answers Answer: . Mitteleters of Pb (N0g) solution added = 47-0 mb. Teren over to trapane 11-20 grams f precăpitale by prepare

- Explanation Following in the Explanation for the above Answers - Giver :- © Melan concentration of Soum Sulfode (Na,s) - 1:50M @ Melar concentration of Pb (403)2 = dioom (moly/1i).

Stat @):- 21 reaction Balanced Chemical Equation for reaction beteren. Nags and Pb(983)2, i Pb(NO3)2, + Ways = Pbs I + 2 Nano (Precipitate) Equation Izcay) (y) - Equation ) )

. We know, the molar mass of head (1) Sulfide (P65) :- precipitate = 239-3 g/mol → Therefor: 1.209 4 Pbs precipitate - Isang (239-3 g/mol) = 0.047 moles Pbs * - Copprox.)

Copprox.) Accoming to Equation ©, in order to produce: 8.847 moles of pbs, we will require : (0.847 moles) of 168, 1.P6 (ro:) moles Since: Mob (res) * Vesters) - 0.047 moles. ori ( 2.60 M mat/) * (You are..) = 0.047 maler. 10.047 moles) or persona = T 200M mok/kr) 0.047h = 47.0 mb. (milliliters)