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Problem 4 (4pts) Recalled Fermats little theorem: For every p, a € N, if p is a prime and pla, then -I = 1 mod p. Use Fermat
the second part of the question can be solved by the chineses remainder theorem.
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Answer #1

100 2 an (1 102 od 13) b = ( med 41) By Fermats little the men gif gid Ca. P): 1. Then at mod p. 13 in prime. x. and ged (713med Mao, X 12 Mod 13 x = 8 mod 47 my chinease Rempaunder the very M=13 M2-41 01:12 8. Now, M., = 13x411 533 Zio m/m = 41 2 mm

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the second part of the question can be solved by the chineses remainder theorem. Problem 4...
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