What mass of NaOH(s) must be added to 1.0 L of 0.058 M NH3 to ensure...

Question

Question

What mass of NaOH(s) must be added to 1.0 L of 0.058 M NH3 to ensure that the percent ionization of NH3 is no greater than 0.

Answer 1

Answer #1

NH3 + H2O ............> NH2- + H3O+

Concentration of H3O+ = 0.058 * (0.0014 / 100) = 8.12 * 10^-7 M

thus

mole of H3O+ = 1.0 L * 8.12 * 10^-7 mole / L = 8.12 * 10^-7 mole.

thus

mole of NaOH needed = 8.12 * 10^-7 mole.

and

mass of NaOh = mole * molar mass = 8.12 * 10^-7 mole * 40 g / mole = 3.25 * 10^-5 g

Answer 2

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