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SRV 111-SURVEYING II-TEST Highwaur CURVEK THE PI IS AT 53+62, I IS 26 20, FOR A HORIZONTAL CIRCULAR AND A DOF 5 HAS BEEN SE
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Gri ven, Stati on of P.1 53+ 6 2 26 20 Def lechion angle at p (4) 50 D) Degree of CuT ve Radius f R): CurVe 5729 578 S729.578chord CLc) Length dt lar () 2 R sin L c 2 260 20 (22) Sin = 2 * 45.916 LC 52.2.044 fH External distomce CE): (Sec )-) (2520)

5362 ft. P.I Chainage of chaimage ot Pe -Chainage t -Tanyot lat -Tangent lagth Chainage of - 268.07 536 2 5093 93 ft 5093.93Incremental chord lengths: Let P be the station atter PC the stati on be fore be. PT n have, We Stahion of (5 P C 93) 0 93 StStahion r P- Number st full chards Shation of P 5 6-51 z 5 Wωve, We f o.9 15 = lo0 ft. C2= 3 = 20.26 ft CnC Deflechion angles1718.90 x 6.07 17 18-90 x C R 60 I145.916 x 60 degrees O 15 175 1718.90 C 3 1 2 R x 60 1718.90 x 1oo 1145.916 x60 2 5 2 30 71

Point Station Incremental chord distance (c) Incremental deflection angle (\delta) Total deflection angle (\Delta)
PC 50+93.93 - -
P1 51 6.07 0\degree9'6'' 0\degree9'6''
P2 52 100 02\degree30'00'' 02\degree39'06''
P3 53 100 02\degree30'00'' 05\degree09'06''
P4 54 100 02\degree30'00'' 07\degree39'06''
P5 55 100 02\degree30'00'' 10\degree09'06''
P6 56 100 02\degree30'00'' 12\degree39'06''
PT 56+20.60 20.6 00\degree30'54'' 13\degree10'00''
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