Question

A recent sociological report states that university students drink 5.705.70 alcoholic drinks per week on average, with a standard deviation of 1.7201.1.7201. Suppose Jason, a policy manager at a local university, decides to take a random sample of 170170 university students to survey them about their drinking habits.

Assuming the students' weekly alcohol consumption follows a normal distribution, determine the standard error of the mean alcohol consumption. Provide your answer with precision to two decimal places.

σ¯¯¯¯Y=

Answer 1

Solution :

Given that,

mean = $\mu$ = 5.70

standard deviation = $\sigma$ = 1.7201

n = 170

$\mu$y = $\mu$ = 5.70

$\sigma$y = $\sigma$ / $\sqrt$ n = 1.7201/ $\sqrt$ 170 = 0.13