Homework Answers
Roblem 21) here I No. moisture content 141 1 mass of moted soil mould com) 18. 1206 1802 Tour 17.0 20:1 23.7 mould volyme (v) 983 3 con 3 Sind malam dry density (19/2) (doma = ?? optimum moisture content jomes=2 Roelative compacttone 974. find (d) lield = 21 Longe of meotstare conintent, Solution - r = n No: bulk of b. bulk tag density of soll Y- Brass of masst soll (KI) Volume of moist soil (m) - volume of mould (on) n =1780.4024 kg/m3 1993.3x10CM 1.955/943.3415 = 1860.489 1.800 quwur - 1910.3140 1.045 laus. 31166 1955. 849 " 1:042/4453 454 195.729 " U + / 9.30 . roy
toater content (0.4) 1 maen dry density (alla) 12-1 1700.4004 18.2 (1 +0:1243 -1500.279 1.152 1673. A w 2018 1 1960 489 1618.0 1910.3140/1.100 = 1621.659 1945 Prod 1619.1016 1953.44/37 = 1579.449 $ 27 Conpalttes carrer - as per graph the mealm dry density as 1622. 1000/m3 offionum moisture content tome 19.0 % Relatre compactter Wedne = (Vd) hield ... (Vor meer labs e field RC = d d) men cab aficed - Rolx Erolmaslah 31/22 - 1573.437 72 - Fo a compartien wat - moisture L Content as per corresporting to graph). range of so the be for jorge of computer moorsture content should be form above 971. of R.C. (100-2t to loot zit ome 987.dome to 1027 of one 090X19 to 1.02xome 1962 to 19-38y. As
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Problem 1 (3 points) The results of a standard Proctor test are given in the following...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
(b) The results of a standard Proctor test are given in the Table Q1. The volume...
(b) The results of a standard Proctor test are given in the Table Q1. The volume of the proctor mould used was 1000 cm? The specific gravity (G) of the soil is 2.65. (1) Plot the graph of dry density (kg/m?) against moisture content (%), the zero air void line (ZAV) and determine the maximum dry density and optimum moisture content. Table Q1: Standard Proctor test result Mass of wet soil in Moisture the mould (kg) content (%) 1.75 13...
A field unit weight determination test for the soil described in Problem 6.6 yielded the following...
A field unit weight
determination test for the soil described in Problem 6.6 yielded
the following data: moisture content=10.5% and moist density=1705
kg/m3. Determine the relative compaction.
6.6: The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m²) of compaction and the optimum moisture content. Volume of Proctor mold (cm) Moisture Content (%) Moist unit weight (kg/m3) Dry unit weight 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 Mass of Wet...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould (g) | 1765 1860 1924 1947 1928 1906 Moisture content (%) 13.1 14.9 16.8 18.9 21.1 23.2 If the volume of the sample mould is 944 cm3, Determine the maximum dry density and optimum moisture content of the clay Draw on the same graph 5% voids ratio line. Sketch the dry density-moisture content curve you expect from modified Proctor compaction...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
Soil Mechanics Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum...
Soil Mechanics
Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum Moisture Content (OMC) of 12% and a maximum dry unit weight of 18.1 kN/m. Given this information, address the following questions. a) The soil was used to construct an embankment on a construction site. A sand cone test indicated that a layer of the compacted fill had a total unit weight of 19.8 kN/m3 and a moisture content of 11%. Specifications call for the...
A proctor test was performed on a soil that has a specific gravity of solids of 2.71. The followi...
A proctor test was performed on a soil that has a specific gravity of solids of 2.71. The following results were obtained: Water content Total Unit 1. Finish calculation and plot Weight (Ib/ftA3) compaction curve 10 13 16 2. What is the max. dry unit weight? 3. What is the optimum moisture 106 119 125 129 128 123 content? What range of moisture is permitted if a contractor must achieve 90% compaction? 4. 20 5. What volume of water must...
A series of Proctor compaction tests were performed on fill material used for a roadway application. The results are shown in the Table below.
A series of Proctor compaction tests were performed on fill material used for a roadway application. The results are shown in the Table below.Data Point No.12345Mass of compacted soil + mould (kg)3.7623.9214.0344.0914.04Moisture content, w (%)4.57.510.112.916.4 The mass of the compaction mould was 2.031 kg. The mould volume was 1×10–3 m3.(a) Compute dry unit weight gd for each data point. (b) Draw the Proctor compaction curve of the soil, and determine the maximum dry unit weight gd max and optimum moisture content...
3. Modified Proctor compaction test results for a soil at a construction site indicated that the...
3. Modified Proctor compaction test results for a soil at a construction site indicated that the maximum dry density Ya = 120 lb/A’ at an optimum water content wopt = 9.0%. Assuming specific gravity of the mineral solids Ga=2.67, calculate: (a) the void ratio at the maximum dry density (b) the degree of saturation S at maximum dry density.
3. Modified Proctor compaction test results for a soil at a construction site indicated that the...
3. Modified Proctor compaction test results for a soil at a construction site indicated that the maximum dry density ya = 125 lb/ft at an optimum water content Wopt = 9.5%. Assuming specific gravity of the mineral solids G=2.65, calculate: (a) the void ratio at the maximum dry density (b) the degree of saturation Sat maximum dry density.
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
(b) The results of a standard Proctor test are given in the Table Q1. The volume of the proctor mould used was 1000 cm? The specific gravity (G) of the soil is 2.65. (1) Plot the graph of dry density (kg/m?) against moisture content (%), the zero air void line (ZAV) and determine the maximum dry density and optimum moisture content. Table Q1: Standard Proctor test result Mass of wet soil in Moisture the mould (kg) content (%) 1.75 13...
A field unit weight
determination test for the soil described in Problem 6.6 yielded
the following data: moisture content=10.5% and moist density=1705
kg/m3. Determine the relative compaction.
6.6: The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m²) of compaction and the optimum moisture content. Volume of Proctor mold (cm) Moisture Content (%) Moist unit weight (kg/m3) Dry unit weight 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 Mass of Wet...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould (g) | 1765 1860 1924 1947 1928 1906 Moisture content (%) 13.1 14.9 16.8 18.9 21.1 23.2 If the volume of the sample mould is 944 cm3, Determine the maximum dry density and optimum moisture content of the clay Draw on the same graph 5% voids ratio line. Sketch the dry density-moisture content curve you expect from modified Proctor compaction...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
Soil Mechanics
Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum Moisture Content (OMC) of 12% and a maximum dry unit weight of 18.1 kN/m. Given this information, address the following questions. a) The soil was used to construct an embankment on a construction site. A sand cone test indicated that a layer of the compacted fill had a total unit weight of 19.8 kN/m3 and a moisture content of 11%. Specifications call for the...
A proctor test was performed on a soil that has a specific gravity of solids of 2.71. The following results were obtained: Water content Total Unit 1. Finish calculation and plot Weight (Ib/ftA3) compaction curve 10 13 16 2. What is the max. dry unit weight? 3. What is the optimum moisture 106 119 125 129 128 123 content? What range of moisture is permitted if a contractor must achieve 90% compaction? 4. 20 5. What volume of water must...
3. Modified Proctor compaction test results for a soil at a construction site indicated that the maximum dry density Ya = 120 lb/A’ at an optimum water content wopt = 9.0%. Assuming specific gravity of the mineral solids Ga=2.67, calculate: (a) the void ratio at the maximum dry density (b) the degree of saturation S at maximum dry density.
3. Modified Proctor compaction test results for a soil at a construction site indicated that the maximum dry density ya = 125 lb/ft at an optimum water content Wopt = 9.5%. Assuming specific gravity of the mineral solids G=2.65, calculate: (a) the void ratio at the maximum dry density (b) the degree of saturation Sat maximum dry density.
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