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A proctor test was performed on a soil that has a specific gravity of solids of 2.71. The followi...
Compaction 1. Why do we compact soils to 90 or 95% Standard Proctor (.e. maximum dry...
Compaction 1. Why do we compact soils to 90 or 95% Standard Proctor (.e. maximum dry unit weight) instead of 100% Standard Proctor? 2. At what saturation is the theoretical minimum void ratio achieved? 3. The following data were determined from a compaction test for a soil with a specific gravity of solids = 2.65 Water content Total Unit Weight (lb/ft) 10 98 106 119 125 128 124 119 (%) Graph the compaction curve (dry unit weight versus water content),...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould (g) | 1765 1860 1924 1947 1928 1906 Moisture content (%) 13.1 14.9 16.8 18.9 21.1 23.2 If the volume of the sample mould is 944 cm3, Determine the maximum dry density and optimum moisture content of the clay Draw on the same graph 5% voids ratio line. Sketch the dry density-moisture content curve you expect from modified Proctor compaction...
Soil Mechanics Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum...
Soil Mechanics
Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum Moisture Content (OMC) of 12% and a maximum dry unit weight of 18.1 kN/m. Given this information, address the following questions. a) The soil was used to construct an embankment on a construction site. A sand cone test indicated that a layer of the compacted fill had a total unit weight of 19.8 kN/m3 and a moisture content of 11%. Specifications call for the...
A series of Proctor compaction tests were performed on fill material used for a roadway application. The results are shown in the Table below.
A series of Proctor compaction tests were performed on fill material used for a roadway application. The results are shown in the Table below.Data Point No.12345Mass of compacted soil + mould (kg)3.7623.9214.0344.0914.04Moisture content, w (%)4.57.510.112.916.4 The mass of the compaction mould was 2.031 kg. The mould volume was 1×10–3 m3.(a) Compute dry unit weight gd for each data point. (b) Draw the Proctor compaction curve of the soil, and determine the maximum dry unit weight gd max and optimum moisture content...
Question 1 (20 points) A standard Proctor test was performed on a soil which has a...
Question 1 (20 points) A standard Proctor test was performed on a soil which has a Gs = 2.70. The moisture content and total density results are shown in the table below. Moisture Content 16% Wet unit weight (KN/m3) 19.1 18% 20.3 20% 20.7 22% 20.0 24% 18.2 a. Calculate the dry unit weight for each sample and type your answers in the first 5 answer boxes below (3 sigs, in KN/m3). b. Calculate the dry unit weight at zero...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
Problem 1 (3 points) The results of a standard Proctor test are given in the following...
Problem 1 (3 points) The results of a standard Proctor test are given in the following table. Moisture Mass of moist soil in the mold (R) Trial no. 1668 1723 1800 1850 1873 8.9 12 1868 a. Determine the maximum dry unit weight of compaction and the opti- mum moisture content. Given: Mold volume = 943.3 cm'. b. Determine the void ratio and the degree of saturation at the optimum moisture content. Given: G, = 2.73 Problem 2 (4 points)...
QUESTION 2 A sand cone test has been performed in a recently compacted fill. The test...
QUESTION 2 A sand cone test has been performed in a recently compacted fill. The test results obtained are as follows: Initial weight of sand cone + sand = 12.51 lb Final weight of sand cone + sand = 3.26 Weight of sand to fill cone = 1.12 lb Weight of soil from hole + bucket =11.42 lb Weight of bucket =0.21 lb Moisture content test: Mass of empty moisture content can = 18.11g Mass of moist soil + can...
3. Modified Proctor compaction test results for a soil at a construction site indicated that the...
3. Modified Proctor compaction test results for a soil at a construction site indicated that the maximum dry density Ya = 120 lb/A’ at an optimum water content wopt = 9.0%. Assuming specific gravity of the mineral solids Ga=2.67, calculate: (a) the void ratio at the maximum dry density (b) the degree of saturation S at maximum dry density.
Compaction 1. Why do we compact soils to 90 or 95% Standard Proctor (.e. maximum dry unit weight) instead of 100% Standard Proctor? 2. At what saturation is the theoretical minimum void ratio achieved? 3. The following data were determined from a compaction test for a soil with a specific gravity of solids = 2.65 Water content Total Unit Weight (lb/ft) 10 98 106 119 125 128 124 119 (%) Graph the compaction curve (dry unit weight versus water content),...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
standard Proctor compaction test conducted on a clay sample gave the following results Weight of wet soil in the mould (g) | 1765 1860 1924 1947 1928 1906 Moisture content (%) 13.1 14.9 16.8 18.9 21.1 23.2 If the volume of the sample mould is 944 cm3, Determine the maximum dry density and optimum moisture content of the clay Draw on the same graph 5% voids ratio line. Sketch the dry density-moisture content curve you expect from modified Proctor compaction...
Soil Mechanics
Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum Moisture Content (OMC) of 12% and a maximum dry unit weight of 18.1 kN/m. Given this information, address the following questions. a) The soil was used to construct an embankment on a construction site. A sand cone test indicated that a layer of the compacted fill had a total unit weight of 19.8 kN/m3 and a moisture content of 11%. Specifications call for the...
Question 1 (20 points) A standard Proctor test was performed on a soil which has a Gs = 2.70. The moisture content and total density results are shown in the table below. Moisture Content 16% Wet unit weight (KN/m3) 19.1 18% 20.3 20% 20.7 22% 20.0 24% 18.2 a. Calculate the dry unit weight for each sample and type your answers in the first 5 answer boxes below (3 sigs, in KN/m3). b. Calculate the dry unit weight at zero...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
Problem 1 (3 points) The results of a standard Proctor test are given in the following table. Moisture Mass of moist soil in the mold (R) Trial no. 1668 1723 1800 1850 1873 8.9 12 1868 a. Determine the maximum dry unit weight of compaction and the opti- mum moisture content. Given: Mold volume = 943.3 cm'. b. Determine the void ratio and the degree of saturation at the optimum moisture content. Given: G, = 2.73 Problem 2 (4 points)...
QUESTION 2 A sand cone test has been performed in a recently compacted fill. The test results obtained are as follows: Initial weight of sand cone + sand = 12.51 lb Final weight of sand cone + sand = 3.26 Weight of sand to fill cone = 1.12 lb Weight of soil from hole + bucket =11.42 lb Weight of bucket =0.21 lb Moisture content test: Mass of empty moisture content can = 18.11g Mass of moist soil + can...
3. Modified Proctor compaction test results for a soil at a construction site indicated that the maximum dry density Ya = 120 lb/A’ at an optimum water content wopt = 9.0%. Assuming specific gravity of the mineral solids Ga=2.67, calculate: (a) the void ratio at the maximum dry density (b) the degree of saturation S at maximum dry density.
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