Homework Answers
Add Answer to:
QUESTION 2 A sand cone test has been performed in a recently compacted fill. The test...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
Soil Mechanics Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum...
Soil Mechanics
Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum Moisture Content (OMC) of 12% and a maximum dry unit weight of 18.1 kN/m. Given this information, address the following questions. a) The soil was used to construct an embankment on a construction site. A sand cone test indicated that a layer of the compacted fill had a total unit weight of 19.8 kN/m3 and a moisture content of 11%. Specifications call for the...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
write nicely thank you bruh this for sand (b) A soil sample from a proposed...
write nicely thank you bruh
this for sand
(b) A soil sample from a proposed road construction in Segamat, Johor was sent to a Geotechnical Laboratory UTHM, for a compaction test. The results of compaction test obtained using modified Proctor compaction test is shown in Figure Q4 (b). 3 hi HELP ME! Predict the maximum dry density (Pmax), optimum moisture content (OMC), the dry density at 95% compaction and the range of moisture content at 95% compaction on dry...
A series of Proctor compaction tests were performed on fill material used for a roadway application. The results are shown in the Table below.
A series of Proctor compaction tests were performed on fill material used for a roadway application. The results are shown in the Table below.Data Point No.12345Mass of compacted soil + mould (kg)3.7623.9214.0344.0914.04Moisture content, w (%)4.57.510.112.916.4 The mass of the compaction mould was 2.031 kg. The mould volume was 1×10–3 m3.(a) Compute dry unit weight gd for each data point. (b) Draw the Proctor compaction curve of the soil, and determine the maximum dry unit weight gd max and optimum moisture content...
Problem 1 (3 points) The results of a standard Proctor test are given in the following...
Problem 1 (3 points) The results of a standard Proctor test are given in the following table. Moisture Mass of moist soil in the mold (R) Trial no. 1668 1723 1800 1850 1873 8.9 12 1868 a. Determine the maximum dry unit weight of compaction and the opti- mum moisture content. Given: Mold volume = 943.3 cm'. b. Determine the void ratio and the degree of saturation at the optimum moisture content. Given: G, = 2.73 Problem 2 (4 points)...
(b) The results of a standard Proctor test are given in the Table Q1. The volume...
(b) The results of a standard Proctor test are given in the Table Q1. The volume of the proctor mould used was 1000 cm? The specific gravity (G) of the soil is 2.65. (1) Plot the graph of dry density (kg/m?) against moisture content (%), the zero air void line (ZAV) and determine the maximum dry density and optimum moisture content. Table Q1: Standard Proctor test result Mass of wet soil in Moisture the mould (kg) content (%) 1.75 13...
2. [10] A segment of interstate highway requires the construction of an embankment of 500,000 yds. The embankment fills to be compacted to a minimum of 90% of Modified Proctor maximum dry den...
2. [10] A segment of interstate highway requires the construction of an embankment of 500,000 yds. The embankment fills to be compacted to a minimum of 90% of Modified Proctor maximum dry density. A source of suitable borrow has been located for construction of the embankment. Tests showed that the required dry density can be achieved with the existing moisture content of the borrow pit material. The following data is provided: Dry unit weight of soil in the borrow pit...
A field unit weight determination test for the soil described in Problem 6.6 yielded the following...
A field unit weight
determination test for the soil described in Problem 6.6 yielded
the following data: moisture content=10.5% and moist density=1705
kg/m3. Determine the relative compaction.
6.6: The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m²) of compaction and the optimum moisture content. Volume of Proctor mold (cm) Moisture Content (%) Moist unit weight (kg/m3) Dry unit weight 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 Mass of Wet...
A proctor test was performed on a soil that has a specific gravity of solids of 2.71. The followi...
A proctor test was performed on a soil that has a specific gravity of solids of 2.71. The following results were obtained: Water content Total Unit 1. Finish calculation and plot Weight (Ib/ftA3) compaction curve 10 13 16 2. What is the max. dry unit weight? 3. What is the optimum moisture 106 119 125 129 128 123 content? What range of moisture is permitted if a contractor must achieve 90% compaction? 4. 20 5. What volume of water must...
The results of a standard Proctor test (ASTM performed in a standard mold with V-1/30 ft are given below Weight of wet soil Water content in the mold (Ibs 3.26 4.15 4.67 4.02 3.63 8.4 10.2 12.3 14.6 16.8 a) Plot the data on a plot of dry unit weight versus water content and determine the maximum dry unit weight and the optimum water content. As the geotechnical engineering consultant involved in the project, based on the results obtained in...
Soil Mechanics
Problem 2 (26 points) Results from a standard Proctor compaction test yield an Optimum Moisture Content (OMC) of 12% and a maximum dry unit weight of 18.1 kN/m. Given this information, address the following questions. a) The soil was used to construct an embankment on a construction site. A sand cone test indicated that a layer of the compacted fill had a total unit weight of 19.8 kN/m3 and a moisture content of 11%. Specifications call for the...
The following results were obtained from standard Proctor compaction tests. Test ID Mass of moist soil (kg) 1 1.633 Standard Proctor Test 2 . 1.841 1.907 1.822 1.756 Moisture Content Test 14 14 Mass of tin empty (g) Mass of tin + wet sample (g) Mass of tin + dry sample (g) 98 62 878280 (a) Calculate moisture content (w) and dry unit weight (ya) for standard Proctor compaction tests. Plot moisture content (w) vs. dry unit weight (yd). Given:...
write nicely thank you bruh
this for sand
(b) A soil sample from a proposed road construction in Segamat, Johor was sent to a Geotechnical Laboratory UTHM, for a compaction test. The results of compaction test obtained using modified Proctor compaction test is shown in Figure Q4 (b). 3 hi HELP ME! Predict the maximum dry density (Pmax), optimum moisture content (OMC), the dry density at 95% compaction and the range of moisture content at 95% compaction on dry...
Problem 1 (3 points) The results of a standard Proctor test are given in the following table. Moisture Mass of moist soil in the mold (R) Trial no. 1668 1723 1800 1850 1873 8.9 12 1868 a. Determine the maximum dry unit weight of compaction and the opti- mum moisture content. Given: Mold volume = 943.3 cm'. b. Determine the void ratio and the degree of saturation at the optimum moisture content. Given: G, = 2.73 Problem 2 (4 points)...
(b) The results of a standard Proctor test are given in the Table Q1. The volume of the proctor mould used was 1000 cm? The specific gravity (G) of the soil is 2.65. (1) Plot the graph of dry density (kg/m?) against moisture content (%), the zero air void line (ZAV) and determine the maximum dry density and optimum moisture content. Table Q1: Standard Proctor test result Mass of wet soil in Moisture the mould (kg) content (%) 1.75 13...
2. [10] A segment of interstate highway requires the construction of an embankment of 500,000 yds. The embankment fills to be compacted to a minimum of 90% of Modified Proctor maximum dry density. A source of suitable borrow has been located for construction of the embankment. Tests showed that the required dry density can be achieved with the existing moisture content of the borrow pit material. The following data is provided: Dry unit weight of soil in the borrow pit...
A field unit weight
determination test for the soil described in Problem 6.6 yielded
the following data: moisture content=10.5% and moist density=1705
kg/m3. Determine the relative compaction.
6.6: The results of a standard Proctor test are given in the following table. Determine the maximum dry density (kg/m²) of compaction and the optimum moisture content. Volume of Proctor mold (cm) Moisture Content (%) Moist unit weight (kg/m3) Dry unit weight 943.3 943.3 943.3 943.3 943.3 943.3 943.3 943.3 Mass of Wet...
A proctor test was performed on a soil that has a specific gravity of solids of 2.71. The following results were obtained: Water content Total Unit 1. Finish calculation and plot Weight (Ib/ftA3) compaction curve 10 13 16 2. What is the max. dry unit weight? 3. What is the optimum moisture 106 119 125 129 128 123 content? What range of moisture is permitted if a contractor must achieve 90% compaction? 4. 20 5. What volume of water must...
Most questions answered within 3 hours.
-
A resistor and the capacitor are used to control the timing in
the RC circuit of...
asked 11 minutes ago -
Five moles of monatomic ideal gas have initial pressure 2.50 ×
103 Pa and initial volume...
asked 11 minutes ago -
Living in a group could bring several disadvantages to an
individual. What are some of the...
asked 29 minutes ago -
Complete and balance the following reactions. In case of no
reaction occurring write NR.
Mix #1:...
asked 34 minutes ago -
If an economy consumes 75% of any increase in income, then an
increase in autonomous investment...
asked 37 minutes ago -
A shotputter throws the shot with an initial speed of 15.8 m/s
at a 38.0 ∘...
asked 53 minutes ago -
Debra and Merina sell electronic equipment and supplies through
their partnership. They wish to expand their...
asked 54 minutes ago -
How does a linear regression allow you to better estimate
trends, costs, and other factors in...
asked 1 hour ago -
1. (15%) Describe the difference between a pull (Kanban), push
and CONWIP production systems.
asked 58 minutes ago -
QUESTION 5
The total area under the Z distribution curve is equal to:
a.
10
b....
asked 1 hour ago -
Using Python
The variables x and y refer to numbers. Write a code segment
that prompts...
asked 1 hour ago -
If
the coefficient of static friction between a box and the floor is
0.35 with what...
asked 1 hour ago