Question

The motor at A develops a power of 280 W and turns the connected pulley at speed of w=95 rpm allowable shear stress is Tallow = 95 MPa. Pulley diameter: DA = 70 mm, DB= 160 mm.

The motor at A develops a power of 280 W and turns the connected pulley at speed of w =95 rpm. The allowable shear stress is allow = 95 MPa. Pulley diameter: D. = 70 mm, D = 160 mm. • Determine the torque at pulley A. • Determine the angular velocity of pulley B. • Determine the torque at pulley B. • Determine the required diameter of the steel shaft on the pulley A.

Answer 1

so Given Daver p= 280w OA : 70 mm Do = 160 mm sedd wa 958pm e allow = 95 mpa. 1. a) Angulan rebuty of pulley A WAZ 20 madls. = 207x95 WA = 9,948 vadis porque at Pulley A TAFR = 280 = 28.14 Nm por que o at TAS 28.14 nm 1 b) Angular rebcity of pelley B We are a lot СА 9.948 59.948 () = 4,352 radis WB 4,352 sadis Angular velocity c) porque at B. Tools 280 = 64,33 mm 4,352 TR= 64.33 form . d) Pallow= TAC . 95 X166 = 28. 14 ( a da-0.01146 m. da = 11,47 mm) į (da) =) ( )= 28114 7x95x10G diameter of shaft