Question

* For the stationcuy fluid shown in the fig the pressure at point B is 25 kPa greater t at point A Determine the specific weight of the manometer frid. (20 pts) P=4h, yap. g Y w= 9800 Nim Manoleter fluid is g=98 mis S.G=sm Given: PB = PA+25 PO-PA = 25 kPa 120 2m 12 Pressure in the left limb below x-x Tam SG= =PA (1.2 x a.81mise x2m) tunidades ? en Rra C Density = 1500 = PA - 23.544 Pressure in the right limb below x-x = PB - (1.5x0.81 m 15²x2m) - (Sm xa.81m 152x2m) = PB- 29.43 -19.625m Eq. tu Anessures PA-23.544= PB-29.43-19.62 sm

Answer 1

nower PB = 1500 kg/m3 Sq=1.2 m • 9.8 mg-2 A-). - -- - 2 m Pa = 1.2 xPwo → density of water 980 legims PA = 1116 kg/m3 pressure at point t is equal to the prekure . at A so now Let PA = Pg - Pegh harm 25 x 103 - 1500*9.8*2 PA=-u.akpa from this level upto the top calculate the press use in both arm PA - Pegx3 = PA - Pagx2 a Pexg e Pag = 2 Peg whes Pes density us 1. fluid Pag Pag: 1176*9.8 of manometer Specific weight of the manometer fluid is we = 11524.8 No3