Question

Question 17 8 pts . In a clinic laboratory, the probability that a blood sample shows cancerous cells is 0.05. Four blood samples are tested, and the samples are independent. . (a) What is the probability that none shows cancerous cells? (4 decimal places) (b) What is the probability that exactly one sample shows cancerous cells? (c) What is the probability that at least one sample shows cancerous cells? . (d) What is the probability that at least two of the samples show cancerous cells?

Answer 1

a) P(None) = (0.95)⁴ = 0.8145

b) P(X = 1)

$= \binom{4}{1}(0.05)^1(0.95)^3$

= 0.1715

c) P(Atleast one) = 1 - P(0) = 1 - 0.8145 = 0.1855

d) P(Atleast two) = 1 - [P(0) + P(1)] = 1 - [0.8145 + 0.1715] = 0.0140