Question

4. (a) Draw the free-body diagram of the beam. (b) Determine the reactions at the supports. 100 lb 400 lb 900 ft-lb 4 ft 4 ft 3 ft

Answer 1

(a) Draw the free - body diagram of the beam (b) Determine the reaction at the supports Sigma f_y = 0 A_y + B-y + 100 - 400 = 0 A_y + B_y - 300 = 0 A_y + B_y = 300 lb - (1) \r\n Sigma M_B = 0 100 times 14 + A_y times 11 - 900 - 400 times 4 = 0 1400 + 11 A_y - 900 - 1600 = 0 11 A_y - 900 - 200 = 0 11 A_y = 1100 A_y = 1100/11 A_y = 100 lb from eq (1) A_y + B_y = 300 lb 100 + B_y = 300 B_y = 200 lb