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6. Consider the iinear transtormation LA: C denned by C 2 3 2 A- 4 1 7 1 Apply the results you will show in Proof #2 to find
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a) LA: 5 ct defined by LA (x) = AX URECO weve to find [LAJA weve ss = standard basis for 65 (e) = {(1,0,0,0,0), (0,1,0,0,0)LA (0,0,0,1,0) = A La C0040) = 697- auw = 000 - oo-o Doo- - 4th coloumn is LA (0,0,0,0,1)=A kn (909) = [33 mod ] 3rieron ror3 Here were to find TLAT, where B = {(0,0, -12,2,2), (0,0100) 690010) (1,0, 12, 2,-2), (0, 1, 18, -3, -3) } LACO,O, -12,2, 2similarly, LA (0,0,1,0,0] =A ooroo -0013 23 152 4 61 62 46171 oo-oo LA CON 5 -- [i] [ET-01-30 O - O -) and cdoumn of LA (0,0,[4] • [1] •[3-[!] 4th column is 0000 Now, LA (0,1,18, -3,-3)=roo13371 23 152 4 61 62 4 61 721 18 – 3x3-3X3 3 +18-385-342 6+182) [LAZY where, r = {(0,2,4,4), (1111), (3567), (1000)} LA (1,0,0,0,0)=A OOOO- - 91-00}+370 tol ONTT -oo0 (written as linear- 4 a+b+60=6 - 0 4a+b+7c = 6 - ② 0-6-) -c=0 )C=0 c=0 in b + c +d=0=) b+d=0=) b=-d co in ④ = 4 a+b=6. ③ c=0 in za+b+50=3 - 2a+LA COO, (0,0) = A - 3rd codoumn is LA (0,0,0,1,0) =A 000-0 40 (0.000) = TE - 017-8-11 [3] A Ano +0 + mhur 5 to - 4th coloumn- 4a+b+ 76=1 cath+60=2 - 0 @ 6- 7 =-11 (=-1 in = 4a+b=8 3 C=-1 in aa+b+562 ) 2a+b=7 ④ ③ - - 2a=1= a=/ b = 7 -1 = 6 = b+c+d=3

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