Question

Review Part A The 1.5 kg physics book in figure is connected by a string to a 550 g coffee cup. The book is given a push up the slope and released with a speed of 3.1 m/s The coefficients of friction are = 0.50 and μk How far does the book slide? Express your answer with the appropriate units. 0.20 (Figure 1) Value Units Submit Part B At the highest point, does the book stick to the slope, or does it slide back down? O stick to the slope Figure O slide back downhill Submit Provide Feedback 20°

Answer 1

F.B.D = > By F.B.D. of cup T = m_c times g Now, by force balance on book, m_B times g sin theta + T + f_r = m_B times a here, f_r = friction force = N times mu_k By force balance in vertical direction of slope, N = m_B times g cos theta m_B = mass of book = 1.5 kg m_C = mass of cup = 550 gm = 0.55 kg So, acceleration of book (a) = m_B times g sin theta + m_c times g + mu_k times m_B times g cos theta/m_B on putting values, theta = 20 degree mu_k = 0.20 So, a = 1.5 times 9.81 times sin (20 degree) + 0.55 times 9.81 + 0.20 times 1.5 times 9.81 times cos (20 degree)/1.5 a = 8.80 m/sec^2 Part - A) By kinematics law V^2_final - V^2_intial = 2 times a times s here, V_initial = 3.1 m/sec V_final = 0
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