21)
specific heat = 1560 J/ oC
Q = Cp dT
= 1560 x (23.5 - 20.3 )
= 4992 J
moles of quinone = 0.1964 / 108.1 = 1.817 x 10^-3
delta H = - Q / n
= - 4992 x 10^-3 / 1.817 x 10^-3
delta H = 2747.6 kJ/mol
11.) please answer and explain A certain objects' temperature increases by 1.0 degree C for every...
If the pressure is very low, ice can sublimate at -70 degree C, instead of melting and then evaporating To calculate the enthalpy of sublimation (Delta H_subl) at such temperature, we can take advantage of the properties of state functions. a. In the T vs. H diagram below, draw a plausible path to go from H_2 O ($) at -70 degree C to H_2 O (g) at the same temperature.