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A galvanic (voltaic) cell consists of an electrode composed of chromium in a 1.0 M chromium(III) ion solution and another ele

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note : please check reduction potentials i used here which exactly matches to your answer or not. if do not match please let me know

oxidation : Cr (s) -----------------> Cr3+ (aq) + 3e- , Eo = -0.74 V     (anode)

reduction :   Ag+ (aq) + e- ----------------> Ag (s) , Eo = 0.799 V   (cathode)

Eocell = Eo cathode - Eo anode

              = 0.799 - (-0.74)

              = 1.54 V

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