Question

A galvanic (voltaic) cell consists of an electrode composed of magnesium in a 1.0 M magnesium ion solution and another electrode composed of copper in a 1.0 M copper(I) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25 °C. Refer to the list of standard reduction potentials. Ecell = | 2.46

Answer 1

Mg2+ + 2 e−   ----->   Mg(s)   E0=−2.372 v

Cu+   +  e−   ---->   Cu(s)   (E0 = +0.520 V
Use standard reduction potential vales to find out cathod and anode.The one with
higher reduction potential is the cathode ,where reduction happens.Other
half cell act as anode where oxidation takes lace
so Mg is anode,Cu cathode
Mg/Mg2+// Cu+/Cu

E0cell = E0cathode-E0anode =
0.520 V-[-2.372 V] = 2.892 V

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