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(d) 2.5 X 10 16 (e) - 1.0 X 10 2. An electron in a TV picture tube is accelerated through a potential difference of 1.0 X 1

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Answer #1

Energy due to potential difference = Ek= Q× V

Where Q = charge of an electron= 1.602×10^(-19) C , and V= 1×10^4 V , therefore

Ek = 1×10^4×1.602×10^(-19) joule  

And 1 eV = 1.602 ×10^(-19) J ,

or 1 Joules = 1÷( 1.602 ×10^(-19) ) eV

Therefore the electron energy is = 1×10^4 eV , hence option (a) is correct.

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