An electron in a cathode ray tube is accelerated through a potential difference of 8.0 kV. What kinetic energy does the electron gain in the process? (e = 1.6 × 10−19 C)
1.3E–15 J
1.0E–21 J
1.0E–15 J
5.0E–16 J
1.3E–21 J
An electron in a cathode ray tube is accelerated through a potential difference of 8.0 kV....
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d =1.5-cm-wide region of uniform magnetic field in the figure(Figure 1). Part A What field strength will deflect the electron by 9 = 11 °?
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 1.8 cm wide region of uniform magnetic field in the figure. x x x x x x x x x OV 10 kV What field strength will deflect the electron by = 11 degrees? Express your answer in mT. B= Preview mT
An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV then passes through the d=2.3-cm-wide region of uniform magnetic field in the figure(Figure 1) Part A What field strength will deflect the electron by θ = 11°?
Physics questionPlease, show work.An electron in a cathode-ray tube is accelerated through a potential difference of 10 kV, then passes through the d = 2.3-cm-wide region of uniform magnetic field in the figure(Figure 1.).Part A What field strength will deflect the electron by theta = 14 degree? Express your answer to two significant figures and include the appropriate units.
An electron in a cathode ray tube accelerates from rest through a potential difference of 2500 V over a distance of 2.0 cm. What speed does this electron acquire?
Electrons are accelerated from rest in an electron gun. They move through a potential difference of 15.0 kV. Determine the resulting kinetic energy of each electron. 11.0 kJ 2.40 × 10-15 J 1.45 × 10-23 J 1.76 × 10-15 J
An electron is a accelerated through a potential difference of 750.0 kV so that it leaves this region with a kinetic energy of 750.0 keV. a) Calculate the mass of the electron in units of eV/c^2 correct to 4 decimal places. b) Calculate the total energy E of the electron in Joules and electron-Volts. c) Calculate the speed of the electron using the relativistic kinetic energy, and the non-relativistic kinetic energy. Express your answer as a fraction times c. d)...
(c) A proton is accelerated from rest through a potential difference of 10 kV. A proton has chargeqproton = +1.6 10-19 C and mass mproton = +1.67 10-27 C i. Calculate the change in potential energy of the proton, in your answer you must explicitly state whether it is a gain or loss in potential energy. ii. Calculate the final velocity of the proton.
An electron in the beam of a TV picture tube is accelerated by a potential difference of 1.92 kV . Then it passes through a region of transverse magnetic field, where it moves in a circular arc with a radius of 0.186 m . What is the magnitude of the field? Use 9.11×10−31 kg for the mass of an electron and 1.60×10−19 C for the magnitude of the charge on an electron.
An electron beam moves toward a cathode ray tube screen, which is 30 cm away from the negative electrode. The electrons are accelerated by a potential difference of 14 kV. Estimate the maximum displacement of the electron beam caused by Earth's magnetic field. The average magnetic field at the surface of Earth is roughly BE = 45×10−6T. answer with units