Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 5.7 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 10 samples is 6.1 ppm with a variance of 0.25. Does the data support the claim at the 0.01 level? Assume the population distribution is approximately normal. Step 4 of 5 : Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places.
H0: Null Hypothesis: = 5.7
HA: Alternative Hypothesis: > 5.7
SE = s/
= /
= 1.5811
Test Statistic is given by:
t = (6.1 - 5.7)/1.5811
= 0.253
= 0.01
ndf = n - 1 = 10 - 1 = 9
One Tail - Right Side Test
From Table, critical value of t = 2.821
Decision Rule:
Reject null hypothesis if t > 2.821
Since the calculated value of t is less than critical value, the difference is not significant. Fail to reject null hypothesis.
Conclusion:
The data do not support the claim that the current ozone level is
at an excess level.
Answer to Question asked:
Question:
Determine the decision rule for rejecting the null hypothesis.
Answer :
Reject null hypothesis if t > 2.821
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