Question

Q49. If 306 C of charge is passed through a solution of Cu(NOs)h(aq), calculate the number of moles of copper deposited on the cathode. a) 0.00634 mol b) 0.00317 mol c) 0.00159 mol d) 1.00 mol e) 2.00 mol

Answer 1

Cu2+       +   2e-       —> Cu

1 mol of Cu requires 2 mol of electron

1 mol of electron is same as 96500 Coulomb

so,

1 mol of Cu requires 2*96500 = 193000 Coulomb

mol of Cu deposited = total charge passed / charge required by 1 mol of copper

= 306/193000

= 0.00159 mol

Answer: c