calculate the amount of Potassium Fluoride (MW=58.1) required to prepare a 153.9 mL of a 5.40%...

Question

Question

calculate the amount of Potassium Fluoride (MW=58.1) required to prepare a 153.9 mL of a 5.40% (w/v) solution of Potassium Fluoride.

Answer 1

Answer #1

volume of solution required to prepare = 153.9 ml , required w/v% = 5.40%

we know formula mass of solute in gram = (volume of solution in ml x w/v%)/100

substitute values to find gram of potassium fluoride solute required

mass of potassium fluoride solute required = (153.9 x 5.40)/100 = 8.3106 gram

ans 8.3106 gram of potassium fluoride is required to prepare 153.9 ml of 5.40 % (w/v) solution of potassium fluoride

Answer 2

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