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10 mL saturated potassium oxalate , potassium oxalate Mw = 184.23 g mol-1, solubility of potassium...

10 mL saturated potassium oxalate , potassium oxalate Mw = 184.23 g mol-1, solubility of potassium oxalate in water at 25°C = 360. calculate the concentration a saturated solution of potassium oxalate

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Answer #1

solubility of potassium oxalate in water at 25°C = 360 mg / ml = 0.360 g / ml

0.360 g K2C2O4 . H2O = mass / molar mass = 0.360 g / 184.23 = 1.954 * 10^-3 mole.

thus

mole of K2C2O4 in one ml = 1.954 * 10^-3 mole.

1 ml = 0.001 L

thus

concentration a saturated solution of potassium oxalate = 1.954 * 10^-3 mole / 0.001 L = 1.954 mole / L

therefore,

concentration a saturated solution of potassium oxalate = 1.954 mole / L

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