Determine the solubility of 2.15g of N2(g) at 35°C dissolved in 3.0L of solvent.

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Answer 1

Answer #1

N0 of moles of N2 gas, n = 2.15g×「mol N2 = 0.0767 mol N. Volume of the gas, 3,0 L Temperature, T- 35° C+273- 308 K Gas consta

Answer 2

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