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You have 0.500 moles of lead nitrate and 1.50 moles of potassium chloride available for this...

You have 0.500 moles of lead nitrate and 1.50 moles of potassium chloride available for this reaction. use stoichiometric ratios to determine the limiting and excess reagents for this reaction (in moles), by calculating the moles of the PbCl2 product (precipitate) formed. show all your work.

Pb(No3)2 (___)+KCl(___)---->PbCl2(___)+KNO3(___)

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Answer #1

Balance reaction - Pb(NO₃) + akce Pbcl + 2 KNO3 Cag) lag) (s) cag) I mole Pb(NO₂), require 2 mole kae. So, 0.500 mole Pb(NO3)

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