If 2.5 mol of lead (II) nitrate reacts with 2.32 mol of sodium chloride in the following unbalanced equation which reactant is the limiting reactant? How many moles of lead (II) chloride should form?
Pb(NO3)2 (aq) + NaCl (aq) --> PbCl2 (s) + NaNo3
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If 2.5 mol of lead (II) nitrate reacts with 2.32 mol of sodium chloride in the following unbalanced equation which reactant is the limiting reactant? How many moles of lead (II) chloride should form?
8. Select the net ionic equation for the reaction between sodium chloride and lead(II) nitrate, A) NaCl(s) → Na'(aq) + Cl(aq) B) Na'(aq) + NO, (aq) → NaNO3(s) C) Pb(NO3)(s) → Pb2(aq) + 2NO, (aq) D) Pb2+ (aq) + 2Cl(aq) → PbCl2(s) E) 2 NaCl(aq) + Pb(NO3)2(aq) → 2NaNO3(s) + PbCl (s)
In lab, students are asked to prepare solid lead (II) chloride (PbCly) according to the following balanced chemical equation. If there is excess lead (II) nitrate, Pb(NO3)2, solution, then how many grams of lead (II) chloride can be made from 100.0 mL of a 0.425 M sodium chloride (NaCl) solution? Pb(NO3)2 (aq) + 2 NaCl (aq) -- PbCl2 (s) + 2 NaNO3(aq) HTML Editor BIVA L = 三 x 1 12pt Paragraph O words
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